25x^2-112x-80=0

Solution for 25x^2-112x-80=0 equation:

25x^2-112x-80=0

a = 25; b = -112; c = -80;
Δ = b2-4ac
Δ = -1122-4·25·(-80)
Δ = 20544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20544}=\sqrt{64*321}=\sqrt{64}*\sqrt{321}=8\sqrt{321}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-112)-8\sqrt{321}}{2*25}=\frac{112-8\sqrt{321}}{50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-112)+8\sqrt{321}}{2*25}=\frac{112+8\sqrt{321}}{50}
$